101k views
0 votes
How do you make a 500 ml solution that is 1.5% (w/v) NaCl, 2 mm tris, 7% (w/v) powdered milk and 0.02% (v/v) antifoam?

1 Answer

2 votes

Final answer:

To make a 500 ml solution with a concentration of 1.5% (w/v) NaCl, you would need to weigh out approximately 16.24 grams of NaCl.

Step-by-step explanation:

To make a 500 ml solution with a concentration of 1.5% (w/v) NaCl, you would need to calculate the mass of NaCl required. The formula to calculate the mass (in grams) of any substance is given by:

Mass (g) = volume (ml) * concentration (%) * density (g/ml)

For NaCl, the density is approximately 2.165 g/ml. Substituting the values into the formula:

Mass (g) = 500 ml * 1.5% * 2.165 g/ml = 16.2375 g

Therefore, you would need to weigh out approximately 16.24 grams of NaCl to prepare a 500 ml solution with a concentration of 1.5% (w/v) NaCl.

User Kartikluke
by
7.8k points