Final answer:
After converting both Sally's and her dog's ages into days, we find that Sally is older by approximately 4 months, although this does not match the provided options and seems to indicate a discrepancy in the question.
Step-by-step explanation:
The subject of this question involves comparing ages and is a mathematics problem typically suitable for a middle school student. To determine who is older between Sally and her dog, we need to first convert Sally's age into days and then compare it to the age of her dog in days.
Sally is 12 years and 3 months old. Since each year has 12 months, Sally's age in months is 12 years × 12 months/year + 3 months, which equals 147 months. To find her age in days, we need the number of days per month. Assuming an average month length of 30.4375 days (which accounts for leap years), we multiply 147 months by 30.4375 days/month to find Sally's age in days:
147 months × 30.4375 days/month = 4,474.31 days
Thus, Sally is approximately 4,474 days old. Now, we compare this to her dog's age, which is 4,350 days:
Sally: 4,474 days
Dog: 4,350 days
Since Sally's age in days is greater than the dog's, Sally is older. To find out by how many months Sally is older, we take the difference in days and divide it by the average number of days in a month:
(4,474 days - 4,350 days) ÷ 30.4375 days/month = 4.07 months
Rounding down to the nearest whole month, it comes to about 4 months difference, as fractions of months are not offered as options, this would mean Sally is older but none of the options exactly match. It seems there might be a typo in the provided answers or an error was made. However, the closest correct answer, if we ignore the rounding, would be that Sally is older by 4 months.