Question

In the school store, markers cost $0.25 each, and pencils cost $0.10 each. Edward spent $2.40 to buy a total of 12 markers and pencils. How many markers did Edward buy?

A) 6
B) 8
C) 10
D) 12

Answer 1

To find out how many markers Edward bought, we can set up a system of equations using the given information, solve it using the elimination method, and find that Edward bought 8 markers.

Step-by-step explanation:

To find out how many markers Edward bought, we can set up an equation using the given information. Let's represent the number of markers as 'm' and the number of pencils as 'p'. We know that markers cost $0.25 each, so the cost of 'm' markers would be $0.25 * 'm'. Similarly, pencils cost $0.10 each, so the cost of 'p' pencils would be $0.10 * 'p'.

The total cost of the markers and pencils that Edward bought is $2.40. So, we can write the equation: 0.25m + 0.10p = 2.40.

We also know that Edward bought a total of 12 markers and pencils, so we can write another equation: m + p = 12.

We now have a system of two equations:

0.25m + 0.10p = 2.40 (Equation 1)

m + p = 12 (Equation 2)

To solve this system of equations, we can use substitution or elimination method. Let's use the elimination method:

1. Multiply Equation 2 by 0.25 to make the coefficients of 'm' in both equations the same: 0.25(m + p) = 0.25(12) => 0.25m + 0.25p = 3
2. Subtract Equation 1 from the equation obtained in step 1 to eliminate 'm': (0.25m + 0.25p) - (0.25m + 0.10p) = 3 - 2.40 => 0.25p - 0.10p = 0.60 => 0.15p = 0.60
3. Divide both sides of the equation by 0.15 to solve for 'p': p = 0.60 / 0.15 => p = 4
4. Substitute the value of 'p' into Equation 2 to solve for 'm': m + 4 = 12 => m = 12 - 4 => m = 8

Therefore, Edward bought 8 markers.