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Divide: (2x^3+4x^2-5)/(x+3)

User Neurozen
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2 Answers

4 votes

Answer:

Explanation:


(2x^3+4x^2-5)/(x+3)=(2x^3+6x^2-2x^2-6x+6x+18-23)/(x+3)=((2x^2-2x+6)(x+3)-23)/(x+3)=\\=2x^2-2x+6-(23)/(x+3)

User Ebullient
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6 votes

answer:

To divide the expression (2x^3 + 4x^2 - 5) by (x + 3), we can use polynomial long division. Here's how:

1. Divide the first term of the numerator (2x^3) by the first term of the denominator (x). The result is 2x^2.

2. Multiply the entire denominator (x + 3) by the result from step 1 (2x^2). The result is 2x^3 + 6x^2.

3. Subtract the result from step 2 from the numerator (2x^3 + 4x^2 - 5) to get the remainder. The remainder is -2x^2 - 5.

4. Bring down the next term from the numerator (-2x^2) and divide it by the first term of the denominator (x). The result is -2x.

5. Multiply the entire denominator (x + 3) by the result from step 4 (-2x). The result is -2x^2 - 6x.

6. Subtract the result from step 5 from the remainder (-2x^2 - 5) to get the new remainder. The new remainder is x - 5.

7. Bring down the next term from the numerator (x) and divide it by the first term of the denominator (x). The result is 1.

8. Multiply the entire denominator (x + 3) by the result from step 7 (1). The result is x + 3.

9. Subtract the result from step 8 from the new remainder (x - 5) to get the final remainder. The final remainder is -8.

Therefore, the division of (2x^3 + 4x^2 - 5) by (x + 3) is equal to 2x^2 - 2x + 1, with a remainder of -8.

We can write this as the quotient (2x^2 - 2x + 1) plus the remainder (-8), all divided by the original denominator (x + 3).

So the final expression is: (2x^2 - 2x + 1 - 8)/(x + 3), which simplifies to (2x^2 - 2x - 7)/(x + 3).

i did it !!

User Vigamage
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