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How many atoms are there in 38 g of iron (Fe)?

A) 6.02 x 10²³ atoms
B) 3.44 x 10²⁴ atoms
C) 9.81 x 10²² atoms
D) 1.25 x 10²⁵ atoms

User Mannu
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1 Answer

1 vote

Final answer:

To find the number of atoms in 38 g of iron, the molar mass of iron (55.8 g/mol) is used to find the number of moles, which is then multiplied by Avogadro's number. The calculation yields approximately 4.10 × 1022 atoms, which is not an exact match for any of the provided options, but is closest to option C, suggesting a possible mistake in the provided answers.

Step-by-step explanation:

The question is asking how many atoms are in 38 g of iron (Fe). To find this, we first need to determine the molar mass of iron, which is 55.8 g/mol according to the periodic table. Then, you divide 38 g by the molar mass to obtain the number of moles of iron.

38 g ÷ 55.8 g/mol = approximately 0.681 mol of Fe.

Next, we use Avogadro's number, which is 6.022 × 1023 atoms/mol, to calculate the total number of iron atoms.

0.681 mol × 6.022 × 1023 atoms/mol = approximately 4.10 × 1022 atoms of Fe.

Looking at the options given, none of them matches our calculation. However, when we recalculate accurately, we should get:

0.681 mol × 6.022 × 1023 atoms/mol = approximately 4.10 × 1022 atoms of Fe.

Therefore, the correct answer, according to our calculations, would be closest to option C) 9.81 × 1022 atoms, assuming there was a mistake in the original answers provided.

User Paul Rumkin
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