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The net horizontal force on a box

f as a function of the horizontal position
x is shown below. What is the work done on the box from
x=0m to
12m? Round answer to two significant digits.

a. 240 J
b. 480 J
c. 720 J
d. 960 J

1 Answer

4 votes

Final answer:

The work done on the box from x = 0m to 12m is 32Nm, which is equivalent to approximately 30J.

Step-by-step explanation:

The work done on the box can be calculated by finding the area under the curve of the force versus distance graph. From x = 0m to x = 12m, the area under the curve can be divided into two parts: the rectangular portion and the triangular portion. The rectangular portion has a height of 4N and a width of 4m, thus its area is 4N * 4m = 16Nm. The triangular portion has a base of 8m and a height of 4N, thus its area is 1/2 * 8m * 4N = 16Nm. Therefore, the total work done on the box is 16Nm + 16Nm = 32Nm, which can be rounded to 30J.

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