Question

How many adults and how many students attended the chicken dinner fundraiser if there were 92 people who attended, adults were charged $10, and students were charged $7, and the fundraiser collected a total of $731?

a) 60 adults and 32 students
b) 50 adults and 42 students
c) 40 adults and 52 students
d) 30 adults and 62 students

Answer 1

There were 29 adults and 63 students who attended the chicken dinner fundraiser.

Step-by-step explanation:

To solve this problem, we can set up a system of equations based on the given information. Let's denote the number of adults as 'a' and the number of students as 's'.

We know that there were 92 people in total, so we can write the equation: a + s = 92

We also know that the total amount collected was $731, with adults paying $10 and students paying $7. So we can write another equation: 10a + 7s = 731

Now we can solve this system of equations to find the values of 'a' and 's'.

Multiplying the first equation by 7, we get 7a + 7s = 644. Subtracting this equation from the second equation, we have 10a + 7s - 7a - 7s = 731 - 644. Simplifying this, we get 3a = 87. Dividing both sides by 3, we find that a = 29.

Substituting this value back into the first equation, we get 29 + s = 92. Solving for s, we find that s = 63.

Therefore, there were 29 adults and 63 students who attended the chicken dinner fundraiser.