Final answer:
Using the kinematic equations for uniformly accelerated motion, the distance travelled by a bus that starts from rest with an acceleration of 2 m/s^2 after 2 seconds is 8 meters, and its final velocity is 4 m/s.
Step-by-step explanation:
The question asks us to find the distance travelled and the velocity of a bus after 2 seconds if it starts from rest with an acceleration of 2m/s2. To solve this, we can use the kinematic equations for uniformly accelerated motion, namely:
- Distance (s) = ut + (1/2)at2
- Final velocity (v) = u + at
Where:
- u = initial velocity = 0 m/s (since the bus starts from rest)
- a = acceleration = 2 m/s2
- t = time = 2 s
Using the first equation:
Distance (s) = 0*(2) + (1/2)(2)(22) = 0 + 2*4 = 8 meters.
And using the second equation:
Final velocity (v) = 0 + (2)(2) = 4 m/s.
Therefore, the bus travels 8 meters and reaches a velocity of 4 m/s after 2 seconds.