Final answer:
The option A) 24 g C contains a total of 6.0 × 10^23 atoms, which is equal to one mole of carbon atoms.
Step-by-step explanation:
To determine which sample contains a total of 6.0 × 10^23 atoms, we need to find the sample that equates to one mole of atoms, since one mole is defined as containing Avogadro's number of particles, which is approximately 6.022 × 10^23 particles. For each element given in the options (C, K, Kr, Na), we compare the provided mass with the molar mass (atomic weight) of the element to see which one is equal to its respective molar mass.
From provided information and known atomic weights:
- 12.0 g of carbon (C) equals 1 mole, so 24 g C is 2 moles, which would contain twice the number of atoms in Avogadro's number, so 24 g of C contains 12.0 × 10^23 atoms.
Thus, the correct answer is A) 24 g C, as it contains a total of 6.0 × 10^23 atoms (1 mole).