Question

The horse is galloping at 13 m/s. Five seconds later, after climbing the hill, the horse is moving at 5.5 m/s. Find the acceleration that describes this change in velocity.

Answer 1

The average acceleration that describes the change in velocity of the horse is -1.5 m/s².

Step-by-step explanation:

The average acceleration that describes the change in velocity of the horse can be found using the equation:

Acceleration (a) = Change in Velocity (v) / Time (t)

Given that the initial velocity (u) of the horse is 13 m/s and the final velocity (v) is 5.5 m/s, the change in velocity (Δv) is:

Δv = v - u = 5.5 m/s - 13 m/s = -7.5 m/s

The time interval (t) is 5 seconds. Substituting the values into the equation:

a = Δv / t = -7.5 m/s / 5 s = -1.5 m/s²

Therefore, the acceleration is -1.5 m/s².