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Find the first three terms, in ascending powers of x, in the expansions of:

(A) (1-x)^6

A) 1 - 6x + 15x^2
B) 1 + 6x + 15x^2
C) 1 - 6x + 21x^2
D) 1 + 6x + 21x^2

User Anujin
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1 Answer

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Final answer:

The first three terms in the expansion of (1 - x)^6 are found using the binomial theorem as follows: the first term is 1, the second term is -6x, and the third term is 15x^2. So, the correct answer is A) 1 - 6x + 15x^2.

Step-by-step explanation:

To find the first three terms, in ascending powers of x, in the expansion of (1 - x)^6, we use the binomial theorem. The binomial theorem expresses the expansion of a binomial raised to a power as a sum of terms involving the original binomial's coefficients.

The general form of the binomial theorem is (a + b)^n = a^n + (n choose 1)a^(n-1)b + (n choose 2)a^(n-2)b^2 + ..., where (n choose k) represents the binomial coefficient.

For the given binomial (1 - x)^6, applying the binomial theorem yields the following terms:

The first term (with x^0): (1)^6 = 1

The second term (with x^1): (6 choose 1)(1)^5(-x) = -6x

The third term (with x^2): (6 choose 2)(1)^4(-x)^2 = 15x^2

Therefore, the first three terms of the expansion in ascending powers of x are 1 - 6x + 15x^2.

Hence, the correct answer is Option A: 1 - 6x + 15x^2.

User Cristian Contrera
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