Question

1. 2k^0 x (3k^2)^3 x 1000^0

2. 32(h^-3)= 4. find h.
3. Solve for t in
a.)3×9^1+t = 27^-t
b.) 9^2t-3 ÷ 3t+3 =1
4. Find x in 9^2x+1 = 81^x-2 ÷ 3x​

Answer 1

To solve for h in the equation 32(h^-3) = 4, we can divide both sides by 32 and then take the cube root to find that h = 1/2.

Step-by-step explanation:

To solve for h, we can start by dividing both sides of the equation by 32 to isolate the variable. This gives us (h^-3) = 4/32 = 1/8. Taking the cube root of both sides of the equation, we get h = 1/∛8 = 1/2.