Question

In the given figure, if the coefficient of friction between the block and the surface is 0.1, then find the acceleration produced by the resultant force acting on the block (taking g = 10 m/s²).

(A) 3 m/s²
(B) 2 m/s²
(C) 5 m/s²
(D) 0.5 m/s²

Answer 1

The acceleration produced by the resultant force acting on the block is 3 m/s²

Step-by-step explanation:

To find the acceleration produced by the resultant force acting on the block, we first need to calculate the net force acting on the block. The net force can be found by subtracting the frictional force from the gravitational force. The frictional force can be found by multiplying the coefficient of friction with the normal force. In this case, the normal force is equal to the gravitational force, which is 40 N.

So, the frictional force is 0.1 * 40 N = 4 N. Subtracting this from the gravitational force of 40 N gives us a net force of 36 N.

Using Newton's second law (F = ma), we can now calculate the acceleration. Rearranging the equation gives us a = F/m = 36 N / 10 kg = 3 m/s².