Question

Jackie buys 3 hot dogs and 1 pretzel from a restaurant for $12.25. Sylvia buys 2 hot dogs and 2 pretzels from the same restaurant for $16.50. Which system of equations can be used to determine the price of the hot dog (h) and a pretzel (p) at the restaurant?

A. 3h + p = 12.25
2h + 2p = 16.50
B. 2h + 2p = 12.25
3h + p = 16.50
C. 3h + p = 16.50
2h + 2p = 12.25
D. 2h + 2p = 16.50
3h + p = 12.25

Answer 1

The system of equations that can be used to determine the price of the hot dog (h) and pretzel (p) at the restaurant is option D: 2h + 2p = 16.50, 3h + p = 12.25. To solve the system, use the method of elimination or substitution.

Step-by-step explanation:

The system of equations that can be used to determine the price of the hot dog (h) and a pretzel (p) at the restaurant is option D. The system of equations is:

• 2h + 2p = 16.50
• 3h + p = 12.25

To solve this system of equations, we can use the method of substitution or elimination. Let's use the method of elimination:

1. Multiply the first equation by 3 to eliminate the h term: 6h + 6p = 49.50
2. Subtract the second equation from the first equation: 6h + 6p - (3h + p) = 49.50 - 12.25
3. Simplify: 3h + 5p = 37.25

Now we have a new system of equations: 3h + 5p = 37.25 and 3h + p = 12.25. We can solve this system using the method of substitution or elimination to find the values of h and p.