Final Answer:
To calculate the percent yield, we need to compare the actual yield (what was obtained in the experiment) with the theoretical yield (what could be obtained based on stoichiometry). The percent yield, we need to compare the actual yield is 45.52%.
Step-by-step explanation:
To calculate the percent yield, we need to compare the actual yield (what was obtained in the experiment) with the theoretical yield (what could be obtained based on stoichiometry).
1. Determine moles of sulfur (S) and aluminum (Al):
moles of S =

moles of Al =

moles of S =
≈ 0.15 mol
moles of Al =
≈ 0.20 mol
2. Determine the limiting reactant:
The limiting reactant is the one that forms fewer moles of the product. From the balanced equation 3 S + 2 Al → Al₂S₃, we see that 3 moles of sulfur react with 2 moles of aluminum to form 1 mole of aluminum sulfide.
For sulfur:
= 0.05 mol Al₂S₃
For aluminum:
= 0.10 mol Al₂S₃
The limiting reactant is sulfur.
3. Calculate the theoretical yield of aluminum sulfide (Al₂S₃):
moles Al₂S₃ =

moles Al₂S₃ =
= 0.05 mol
Theoretical yield = moles Al₂S₃ × molar mass of Al₂S₃
Theoretical yield = 0.05 mol × (2 × 26.98 g/mol + 3 × 32.06 g/mol)
4. Calculate the percent yield:
Percent yield =

Percent yield =

Percent yield = 45.52
So, the percent yield, we need to compare the actual yield is 45.52%.