Question

An object starts moving from rest by constant acceleration. The distance covered in the 7th second is greater than in the 1st second by:

a) 4 times
b) 13 times
c) 11 times
d) 7 times
e) 3 times

Answer 1

The distance covered in the 7th second is greater than in the 1st second by 4 times.

Step-by-step explanation:

The distance covered in the 7th second is greater than in the 1st second by 4 times.

When an object starts from rest and accelerates with constant acceleration, the distance covered in each subsequent second is determined by multiplying the time squared by twice the acceleration. In this case, the distance covered in the 1st second is given by 1 x (2 x acceleration), and the distance covered in the 7th second is given by 7 x (2 x acceleration). In the 7th second, the time squared is 49 times greater than in the 1st second (7^2 = 49), so the distance covered in the 7th second is 49 times greater than in the 1st second.

Therefore, the correct answer is option d) 4 times.