Final answer:
The energy transferred to an atom that absorbs a photon with a wavelength of 3.0 picometers is 6.63 x 10^-14 J.
Step-by-step explanation:
The energy of a photon can be calculated using the formula E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the photon.
In this case, we are given the wavelength of the photon, which is 3.0 picometers (pm).
To find the frequency, we can use the formula f = c/λ, where c is the speed of light and λ is the wavelength. Substituting the given values, we get f = (3.00 x 10^8 m/s) / (3.0 x 10^-12 m) = 1.00 x 10^20 Hz.
Now, we can calculate the energy using the formula E = hf = (6.63 x 10^-34 J·s) x (1.00 x 10^20 Hz) = 6.63 x 10^-14 J.