Question

A set of 50 numbers consists of nine 7s, ten 8s, twelve 9s, ten 10s, five 11s, and the remainder were 12s. Find the mean of the numbers.

Answer 1

Given:

The total number is 50.

A set of 50 numbers consists of nine 7s, ten 8s, twelve 9s, ten 10s, five 11s, and the remainder were 12s.

Required:

To find the mean.

Step-by-step explanation:

Here nine 7s, ten 8s, twelve 9s, ten 10s, five 11s, and the remainder were 12s.

So the remaining number is

`\begin{gathered} =50-(9+10+12+5) \\ =50-36 \\ =14 \end{gathered}`

Now the mean is

`\begin{gathered} =(9*7+10*8+12*9+5*11+14*12)/(50) \\ \\ =(63+80+108+55+168)/(50) \\ \\ =(474)/(50) \\ \\ =9.48 \end{gathered}`

Final Answer:

The mean is 9.48