Question

What is the distance between the points (-1,2) and (2,6)?Hey there Ms or Mr could you please help me out? Just a heads up this isn't a quiz it's my homework assignment for today, it's about Properties of quadrilaterals.

Answer 1

A. 5

Step-by-step explanation:

Given the points (-1,2) and (2,6):

To find the distance between the points, we use the distance formula:

`Distance=√((x_2-x_1)^2+(y_2-y_1)^2)`
`\begin{gathered} (x_1,y_1)=(-1,2) \\ (x_2,y_2)=(2,6) \\ \implies Distance=\sqrt[]{(2-(-1))^2+(6-2)^2} \\ =\sqrt[]{(2+1)^2+(6-2)^2} \\ =\sqrt[]{3^2+4^2} \\ =\sqrt[]{25} \\ =5\text{ units} \end{gathered}`

The distance between the given points is 5 units.