Final answer:
The magnitude and direction of the net force on the sailboat can be calculated by considering the individual forces acting on it. In this case, the sailboat is acted on by a force of 2.00 × 10³ N toward the east and a force of 3.00 × 10³ N in a direction 45° north of east. To find the magnitude of the resulting acceleration, we can use vector addition.
Step-by-step explanation:
The magnitude and direction of the net force on the sailboat can be calculated by considering the individual forces acting on it. In this case, the sailboat is acted on by a force of 2.00 × 10³ N toward the east and a force of 3.00 × 10³ N in a direction 45° north of east. To find the magnitude of the resulting acceleration, we can use vector addition:
Magnitude: √((2.00 × 10³ N)^2 + (3.00 × 10³ N)^2) = 3.61 × 10³ N
Direction: tan^(-1)((3.00 × 10³ N)/(2.00 × 10³ N)) = 56.3° north of east