Final answer:
To find the weight of the rock and the tension in the rope, we can use the concept of torques. By setting up equations of torques and using the fact that the system is in equilibrium, we can calculate the weight of the rock and the tension in the rope.
Step-by-step explanation:
To solve this problem, we can use the concept of torques. Torque is the rotational equivalent of force and is calculated by multiplying the force by the distance from the pivot point. In this case, the pivot point is the point where the meter stick is hung.
We know that the system is in equilibrium, which means that the total torque on the meter stick is zero. To find the weight of the rock, we can set up an equation of torques:
Weight of 22.2 N weight = Weight of rock * (100.0 cm - 11.5 cm)
This equation comes from the fact that the torque generated by the 22.2 N weight is equal to the torque generated by the rock. Rearranging this equation, we can find the weight of the rock:
Weight of rock = (Weight of 22.2 N weight) / (100.0 cm - 11.5 cm)
To find the tension in the rope, we can use the fact that the total vertical forces on the meter stick must add up to zero. The tension in the rope is equal to the sum of the weight of the rock and the weight of the 22.2 N weight:
Tension in rope = Weight of rock + Weight of 22.2 N weight
Plugging in the values, we get:
a) Weight of rock = (22.2 N) / (100.0 cm - 11.5 cm) = 0.268 N
b) Tension in rope = 0.268 N + 22.2 N = 22.468 N