Question

Write an inequality to find the three numbers. Let n represent the smallest even number.

A) 90 ≤ n + (n + 2) + (n + 4) < 105
B) 90 < n + (n + 1) + (n + 2) < 105
C) 90 ≤ 3n + 6 < 105
D) 90 ≤ 3n + 5 < 105

Answer 1

The correct inequality to find the three numbers is: C) 90 ≤ 3n + 6 < 105. To solve this inequality, subtract 6 from both sides and divide by 3 to determine the range of values for 'n' that satisfy the given conditions.

Step-by-step explanation:

The correct inequality to find the three numbers is: C) 90 ≤ 3n + 6 < 105.

To solve this inequality, we need to find the range of values for 'n' that satisfy the given conditions. Starting from the left side of the inequality, we have 90 ≤ 3n + 6. Subtracting 6 from both sides, we get 84 ≤ 3n. Dividing both sides by 3, we get 28 ≤ n. Moving to the right side of the inequality, we have 3n + 6 < 105. Subtracting 6 from both sides, we get 3n < 99. Dividing both sides by 3, we get n < 33. Combining the two inequalities, we have 28 ≤ n < 33. Therefore, n can be any integer between 28 (inclusive) and 33 (exclusive).