Question

A cube of gold weighing 155g is heated from 25.0°C to some higher temperature with the absorption of 325 joules of specific heat of gold is 0.030 J/g°C. What is the final temperature of the gold?

Answer 1

To find the final temperature of the gold cube, we can use the formula: Q = mcΔT. In this case, the final temperature of the gold cube is 94.892°C.

Step-by-step explanation:

To find the final temperature of the gold cube, we can use the formula: Q = mcΔT. Where Q is the heat absorbed by the gold cube, m is the mass of the gold cube, c is the specific heat of gold, and ΔT is the change in temperature. In this case, we know that Q = 325 J, m = 155 g, c = 0.030 J/g°C, and the initial temperature is 25.0°C. Let's plug the values into the formula: 325 J = (155 g)(0.030 J/g°C)(T - 25.0°C). Solving for T: 325 J = (4.65 g°C)(T - 25.0°C), T - 25.0°C = 325 J / 4.65 g°C, T - 25.0°C = 69.892°C, T = 94.892°C. Therefore, the final temperature of the gold cube is 94.892°C.