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What is the force of friction between a block of ice that weighs 305 N on the ground if the coefficient of friction is 0.12?

User Bialomazur
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Final answer:

The force of friction between a block of ice and the ground can be calculated using the formula: the force of friction = coefficient of friction * weight. In this case, the force of friction between the block of ice and the ground would be approximately 36.6 N.

Step-by-step explanation:

The force of friction between a block of ice weighing 305 N and the ground can be calculated by multiplying the normal force by the coefficient of friction. Since the weight of the block provides the normal force, and the coefficient of friction is given as 0.12, we can calculate the frictional force as follows: Ffriction = μ × Fnormal. Where μ is the coefficient of friction and Fnormal is the normal force, which is equal to the weight of the block (305 N) in this case: Ffriction = 0.12 × 305 N = 36.6 N. Therefore, the force of friction between the block of ice and the ground is 36.6 N.

User Duburcqa
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