Question

Calculate the volume in liters of oxygen gas at STP required to fully react with 42.5 g of ethyne, C2H2.

2 C2H2(g) + 5 O2(g) --> 4 CO2(g) + 2 H2O(g)

Answer 1

To calculate the volume of oxygen gas required to react with ethyne, use the stoichiometry of the balanced equation.

Step-by-step explanation:

To calculate the volume of oxygen gas required to react with ethyne, we need to use the stoichiometry of the balanced equation. From the balanced equation, we can see that 2 moles of C2H2 react with 5 moles of O2 to produce 4 moles of CO2 and 2 moles of H2O.

First, we need to convert the mass of ethyne to moles using its molar mass of 26 g/mol.

Once we know the moles of C2H2, we can use the stoichiometry to find the moles of O2 that will be required. Finally, we can convert the moles of O2 to volume using the fact that 1 mole of gas at STP occupies 22.4 L.