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The length of a rectangle is two inches less than twice its width. The perimeter is 54 inches. What are the dimensions? (choose two answers)

A) 11 inches width, 18.66 inches length
B) 16 inches width, 35.33 inches length

1 Answer

4 votes

Final answer:

The width of the rectangle is approximately 9.67 inches and the length is approximately 17.34 inches.

Step-by-step explanation:

To solve this problem, let's represent the width of the rectangle as 'w'. According to the problem, the length is two inches less than twice the width, so the length can be represented as '2w - 2' inches. The perimeter of a rectangle is given by the formula: 2(length + width). Substituting the given values, we have: 2((2w - 2) + w) = 54. Simplifying this equation, we get: 6w - 4 = 54. Adding 4 to both sides, we have: 6w = 58. Dividing both sides by 6, we get: w = 9.67. Therefore, the width of the rectangle is approximately 9.67 inches. Plugging this value back into the length equation, we have: length = 2(9.67) - 2 = 17.34 inches (approximately). So, the dimensions of the rectangle are approximately 9.67 inches width and 17.34 inches length.

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