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You are driving in a car which has a mass of 1.0 x 10^3 kg and is traveling at 30.0 km/h. You lose control, and it smashes into a concrete wall, essentially stopping the momentum of your car in 0.10 s.

a) What is the momentum of your car at impact?

b) What force is required to stop the car?

c) If you hit a padded wall instead, which brings the car to a stop in 0.50 s, what force is required?

d) What is the purpose of airbags with respect to momentum and impulse?

1 Answer

1 vote

Final answer:

The car's momentum at impact is 8.33 x 10^3 kg·m/s. The force required to stop the car hitting a concrete wall is 8.33 x 10^4 N, while hitting a padded wall requires a force of 1.67 x 10^4 N. Airbags serve to reduce force on passengers by increasing the time over which the car's momentum is brought to zero.

Step-by-step explanation:

To answer the student's question, we must apply concepts of momentum and Newton's second law. The momentum p of an object is given by the product of its mass m and its velocity v. The force F needed to stop an object is derived from the impulse-momentum theorem, which relates force, change in momentum, and the time over which the force is applied.

Questions and Answers

  • a) The momentum of the car at impact is calculated as p = m × v. First, we must convert the speed from km/h to m/s: 30.0 km/h = 8.33 m/s. Therefore, p = 1.0 × 103 kg × 8.33 m/s = 8.33 × 103 kg·m/s.
  • b) The force required to stop the car is given by F = Δp / Δt, where Δp is the change in momentum (which is equal to the initial momentum, since the final momentum is zero) and Δt is the time over which it changes. F = 8.33 × 103 kg·m/s / 0.10 s = 8.33 × 104 N.
  • c) If the car hits a padded wall and stops in 0.50 s, the force required is F = 8.33 × 103 kg·m/s / 0.50 s = 1.67 × 104 N.
  • d) The purpose of airbags is to increase the time over which the change in momentum (impulse) occurs, thereby reducing the force exerted on passengers, which can reduce injuries during a collision.
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