Question

Mike has 15 coins in his pocket. One third of the coins are dimes, and the rest are nickels. How much money does he have in total? Can you use reasoning to solve the problem?

a. Mike has a total of $0.50 + $0.50 = $1.00.
b. Mike has 8 dimes and 7 nickels, totaling $1.50.
c. Mike has 4 dimes and 11 nickels, totaling $1.05.
d. Mike has 6 dimes and 9 nickels, totaling $0.90.

Answer 1

Mike has 5 dimes and 10 nickels, which are worth 50 cents each, totaling $1.00.

Step-by-step explanation:

To solve the problem of how much money Mike has in total with his coins, we need to determine how many dimes and nickels he has and then calculate their total value. Mike has 15 coins in total. One third of these are dimes, which means 15 coins divided by 3 equals 5 dimes. The rest of the coins are nickels, so he has 15 - 5 = 10 nickels.

Now, we need to find the value of these coins. Each dime is worth 10 cents, and each nickel is worth 5 cents. Therefore, 5 dimes have a value of 5 × 10 cents = 50 cents, and 10 nickels have a value of 10 × 5 cents = 50 cents. Finally, to find the total value of Mike's coins, we add the value of the dimes and the nickels: $0.50 from the dimes + $0.50 from the nickels = $1.00 in total.