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You have a square with vertices R(-3, -1), S(-1, 0), T(0, -2), and U(-2, -3). This square is dilated with a scale factor of k = 4. What are the coordinates of the new vertices of the dilated square?

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Final answer:

To find the coordinates of the new vertices of the dilated square, multiply the x and y values of each vertex by the scale factor. Using a scale factor of 4, the coordinates of the new vertices are R'(-12, -4), S'(-4, 0), T'(0, -8), and U'(-8, -12).

Step-by-step explanation:

To find the coordinates of the new vertices, we will multiply the x and y values of each vertex by the scale factor (k = 4). Let's start with vertex R(-3, -1):

x-coordinate of R' = -3 * 4 = -12

y-coordinate of R' = -1 * 4 = -4

Repeat this process for the other vertices to find the coordinates of the new vertices:

S'(-1, 0)

T'(0, -2)

U'(-2, -3)

The coordinates of the new vertices are:

R'(-12, -4)

S'(-4, 0)

T'(0, -8)

U'(-8, -12)

User Kiran Parmar
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