Question

What are the solutions for the following system of equations?–x^2 + 3y = 203x^2 + 6y = 60 (–2, 8) and (2, 8) (–2, 8) and (0, 10) (2, 8) and (0, 10) (0, –10) and (0, 10)

Answer 1

Given the system of equations below

`\begin{gathered} -x^2+3y=20 \\ 3x^2+6y=60 \end{gathered}`

Using a graphing tool, the graphs of the system of equations is shown below

From the graph above,

The point of intersection of the two graphs is the solution to the system of equation.

Hence, the solution is

`(-2,8)\text{ and }(2,8)`