Final answer:
The negative charges on balloon B will be repelled by balloon A's negative charges, causing the positive charges on balloon B to remain closer to balloon A.
Step-by-step explanation:
When the negative surface of balloon A is brought near balloon B, the charges on balloon B are influenced by the presence of balloon A's charges. Since like charges repel each other, balloon B's negative charges will be repelled and move away from balloon A. This leaves the positive charges in their original position, closer to balloon A. Therefore, the correct answer to what happens to the charges on balloon B is B. Positive charges will move away from balloon A.