Final answer:
The gravitational potential energy of a 10 kg bowling ball from a height of 5 m is 500 joules. When it hits the ground, all potential energy has been converted into kinetic energy, resulting in a speed of 10 m/s. The momentum problem's answer is 50 kg·m/s for a 5 kg ball moving at 10 m/s.
Step-by-step explanation:
To calculate the gravitational potential energy (gravitational potential energy) of a 10 kg bowling ball falling from a height of 5 m, we use the formula:
Potential Energy (PE) = mass (m) × gravity (g) × height (h),
where g is approximately 10 m/s². Therefore, PE = 10 kg × 10 m/s² × 5 m = 500 joules.
When the bowling ball is just before it hits the ground, all of the potential energy has been converted into kinetic energy (KE). The formula to calculate kinetic energy is:
KE = ½ × mass (m) × velocity (v)².
To find the velocity of the bowling ball when it reaches the ground, we set PE equal to KE:
500 joules = ½ × 10 kg × velocity (v)²
Solving for v gives us v = √(500 joules × 2 / 10 kg) = √100 = 10 m/s. So, the speed of the bowling ball when it reaches the ground is 10 m/s.
For Practice Problems, to calculate the momentum (p) of a 5 kg bowling ball with a velocity of 10 m/s, you use the formula:
Momentum (p) = mass (m) × velocity (v), which results in p = 5 kg × 10 m/s = 50 kg·m/s. The correct answer is neither a nor b, but rather 50 kg·m/s.