Final answer:
To prepare a 3.0 mol/L NaOH solution in 0.01 L of water, you need to dissolve 1.2 grams of NaOH, using its molar mass of 40.0 g/mol for the conversion from moles to grams.
Step-by-step explanation:
To calculate the grams of NaOH required to make a 3.0 mol/L solution in 0.01 L of water, we need to use the molar concentration formula which relates moles of solute to volume of solution. The formula is:
Molarity (M) = moles of solute (mol) / volume of solution (L)
We also know the molar mass of NaOH to be 40.0 g/mol. First, we need to determine the number of moles of NaOH needed:
3.0 mol/L × 0.01 L = 0.03 mol NaOH
Now we use the molar mass to convert moles to grams:
0.03 mol NaOH × 40.0 g/mol = 1.2 g NaOH
Thus, to make a 3.0 mol/L solution in 0.01 L of water, you need to dissolve 1.2 grams of NaOH.