Final answer:
By setting up a system of equations and solving them, we find that the farm has 3 dogs and 9 chickens, which satisfies the given conditions.
Step-by-step explanation:
To solve the problem of determining the number of dogs and chickens on a farm, where the total number of animals is 12 and the total number of legs is 30, with at least twice as many chickens as dogs, we can use a system of equations.
Let's define two variables: D for the number of dogs and C for the number of chickens.
The first equation comes from the total number of animals: D + C = 12.
The second equation comes from the total number of legs: 4D + 2C = 30 (because dogs have 4 legs and chickens have 2 legs).
The condition given is that there are at least twice as many chickens as dogs, which can be expressed as: C ≥ 2D.
Now, let's solve this system. By multiplying the first equation by 2, we get 2D + 2C = 24. If we subtract the second equation from this, we get 2D + 2C - (4D + 2C) = 24 - 30, which simplifies to -2D = -6, therefore D = 3.
Using D = 3 in the first equation, we get 3 + C = 12, and solving for C gives us C = 9.
So, the farm has 3 dogs and 9 chickens, which satisfies all the conditions of the problem.