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Find the equation of the straight line PQ where P(-2,4) and Q(2,10). What is the Y intercept?

a. y = 2x + 6
b. y = 2x + 2
c. y = 1/2x + 6
d. y = 1/2x + 2

1 Answer

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Final answer:

The equation of the straight line PQ is y = (3/2)x + 6, and the y-intercept is 6.

Step-by-step explanation:

To find the equation of the straight line PQ where P(-2,4) and Q(2,10), we can use the slope-intercept form of a linear equation, which is y = mx + b.

First, we need to find the slope (m) of the line.

The formula for slope is m = (y2 - y1) / (x2 - x1). Plugging in the coordinates of P and Q, we get m = (10 - 4) / (2 - (-2)) = 6 / 4 = 3/2.

Now we can substitute the slope and one of the points (P) into the equation to find the y-intercept (b).

Using the point-slope form of a linear equation, y - y1 = m(x - x1), we have y - 4 = (3/2)(x - (-2)). Simplifying, we get y - 4 = (3/2)(x + 2).

Expanding and rearranging, y = (3/2)x + 6.

Therefore, the equation of the straight line PQ is y = (3/2)x + 6, and the y-intercept is 6.

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