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A ball is tossed in the air with an initial velocity of 19 ft/sec from a height of 3.5 feet. Which of the following equations represents the ball's height, h, in feet over time, t, in seconds?

A) h = -19t^2 + 3.5
B) h = -16t^2 + 19t + 3.5
C) h= -4.9t^2 + 190 + 3.5
D) h = -4.9t^2 + 16t + 3.5​

1 Answer

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Final answer:

The equation that represents the ball's height, h, in feet over time, t, in seconds is D) h = -4.9t^2 + 16t + 3.5.

Step-by-step explanation:

The equation that represents the ball's height, h, in feet over time, t, in seconds is D) h = -4.9t^2 + 16t + 3.5.

Using the given information that the ball is tossed with an initial velocity of 19 ft/s and from a height of 3.5 feet, we can use the equation of motion h = -4.9t^2 + v0t + h0, where v0 is the initial velocity and h0 is the initial height.

Plugging in the values, we get h = -4.9t^2 + 16t + 3.5, which matches the equation provided in option D.

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