Final answer:
The range is all real numbers greater than or equal to 0, the axis of symmetry is x = 1, and the vertex is (1, 0).
Step-by-step explanation:
The given function is a quadratic function in the form y = a(x-h)^2 + k, where (h, k) is the vertex of the parabola.
For the given function y = 4(x - 1)^(2+5), the vertex is (1, 0) as (h, k).
Therefore, the range is all real numbers greater than or equal to 0, the axis of symmetry is x = 1, and the vertex is (1, 0).