Question

15mg of Bismuth-213, with a half-life of 46 minutes, are administered to a cancer patient in Targeted Alpha Therapy (TAT). How much Bismuth-213 remains 6 hours later?​ A) Approximately 0.9375mg

B) Approximately 1.875mg
C) Approximately 3.75mg
D) Approximately 7.5mg

Answer 1

The amount of the Bismuth-213 that will remain 6 hours later, given that the half-life of 46 minutes, is 0.0661 mg (None of the option)

How to calculate the Bismuth-213 that will remain 6 hours later?

The amount of the Bismuth-213 that will remain 6 hours later can be calculated as shown below:

• Initial amount of Bismuth-213 (N₀) = 15 mg
• Half-life of Bismuth-213 (t½) = 46 minutes
• Time (t) = 6 hours = 6 × 60 = 360 minutes
• Amount remaining 6 hours latter (N) =?

`N = N_0\ *\ ((1)/(2))^{(t)/(t_(1/2))} \\\\N= 15\ *\ ((1)/(2))^{(360)/(46)}\\\\N = 0.0661\ mg`

From the above calculation, the amount of the Bismuth-213 that will remain after 6 hours is 0.0661 mg. None of the option is correct