Question

"A ball begins to roll down a ramp from rest. How fast will the ball be rolling if it

rolls with a constant acceleration of +3.5 m/s^2 for 2 minutes?"

Answer 1

After rolling with a constant acceleration of +3.5 m/s^2 for 2 minutes, the ball will have a final velocity of 420 m/s.

Step-by-step explanation:

To find out how fast the ball will be rolling after accelerating at +3.5 m/s2 for 2 minutes, we use the formula for constant acceleration, which is:

v = u + at

Where:

• v = final velocity
• u = initial velocity (0 m/s since the ball starts from rest)
• a = acceleration (+3.5 m/s2)
• t = time (which needs to be in seconds, so 2 minutes multiplied by 60 = 120 seconds)

Plugging in the values, we get:

v = 0 m/s + (3.5 m/s2 × 120 s)

v = 420 m/s

So the ball will be rolling at a speed of 420 m/s after 2 minutes.

It is important to ensure that units are consistent when performing such calculations, and to remember that the time should be in seconds when using the SI unit system for acceleration.