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While out hiking, Mr. Stancek comes to a small cliff with water at the base. He decides to pick up a stone and tosses it into the water that is 10.0 m below. Mr. Stancek throws the rock horizontally with a velocity of 3.0 m/s. How far out from the edge of the cliff will it hit the water?

A) The stone will hit the water 6.15 meters from the edge of the cliff.
B) The stone will hit the water 30 meters from the edge of the cliff.
C) The stone will hit the water 10 meters from the edge of the cliff.
D) The stone will hit the water 5 meters from the edge of the cliff.

User Hjalmar
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1 Answer

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Final answer:

To find how far out from the edge of the cliff the stone will hit the water, we can use the formula for horizontal motion. By calculating the time it takes for the stone to fall using the equation of motion, and then multiplying it by the horizontal velocity, we find that the stone will hit the water approximately 4.29 meters out from the edge of the cliff.

Step-by-step explanation:

To find how far out from the edge of the cliff the stone will hit the water, we can use the formula for horizontal motion. Since the stone is thrown horizontally with a velocity of 3.0 m/s and the time it takes to hit the water is unknown, we can start by finding the time it takes for the stone to fall 10.0 m using the equation of motion, h = (1/2)gt^2. Rearranging the equation to solve for t, we get t = sqrt((2h)/g), where h is the height of the cliff and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the values, t = sqrt((2 * 10.0) / 9.8) ≈ 1.43 s. Since the stone was thrown horizontally, the horizontal distance it travels during this time is given by the formula d = v * t, where v is the horizontal velocity. Substituting the values, d = 3.0 * 1.43 ≈ 4.29 m. Therefore, the stone will hit the water approximately 4.29 meters out from the edge of the cliff.

Therefore, the correct answer is A) The stone will hit the water 6.15 meters from the edge of the cliff.

User Daniel Veihelmann
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