Question

How many atoms of oxygen are in seven molecules of lead (II) nitrate?

a) 7
b) 6
c) 42
d) 3

Answer 1

There are 42 oxygen atoms in seven molecules of lead (II) nitrate since one molecule contains six oxygen atoms and multiplying by seven gives us 42.Answer is option (c).

Step-by-step explanation:

The question asks us to determine the number of oxygen atoms in seven molecules of lead (II) nitrate. The formula for lead (II) nitrate is Pb(NO3)2. A single molecule of lead (II) nitrate contains six oxygen atoms because the nitrate ion (NO3-) has three oxygen atoms and there are two nitrate ions per molecule.

Therefore, to find the total number of oxygen atoms in seven molecules, we multiply the number of oxygen atoms in one molecule by the seven molecules:

6 oxygen atoms/molecule × 7 molecules = 42 oxygen atoms

So, the correct answer is 42 oxygen atoms.