Final answer:
The molar mass of calcium phosphate (Ca3(PO4)2) is 310.177 g/mol. This is found by summing the atomic masses of 3 calcium atoms, 2 phosphorus atoms, and 8 oxygen atoms.
Step-by-step explanation:
To determine the molar mass of calcium phosphate (Ca3(PO4)2), we must calculate the sum of the masses of all the atoms in one formula unit of the compound. The formula unit of calcium phosphate is made up of 3 calcium atoms, 2 phosphorus atoms, and 8 oxygen atoms. The atomic masses are as follows:
- 3Ca: (3 atoms) (40.078 amu/atom) = 120.234 amu
- 2P: (2 atoms) (30.973761 amu/atom) = 61.947522 amu
- 8O: (8 atoms) (15.9994 amu/atom) = 127.9952 amu
By adding these together, we get the formula mass of Ca3(PO4)2:
120.234 amu + 61.947522 amu + 127.9952 amu = 310.177 amu, which is also expressed as g/mol for molar mass. Therefore, the molar mass of Ca3(PO4)2 is 310.177 g/mol.
The question asks for the molar mass and not the mass of 13.5 moles. As such, the number of moles is not necessary for determining the molar mass. Hence, the answer to the question 'What is the molar mass of 13.5 moles of Ca3(PO4)2?' is not directly dependent on the quantity (13.5 moles) provided in the question.