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What is the equation in slope-Intercept form of the line that crosses the x-axis at 36 and is parallel to the line represented by y=-4/9x+5

A) y = -4/9x +5
B) y = -4/9x -16
C) y = -4/9x +16/1
D) y = 4/9x +16/1

3 Answers

1 vote

Final answer:

The equation in slope-intercept form of the line that crosses the x-axis at 36 and is parallel to the line represented by y = -4/9x + 5 is y = -4/9x + 0.

Step-by-step explanation:

The equation in slope-intercept form of a straight line is given by y = mx + b, where m is the slope and b is the y-intercept.

Since the line is parallel to the line represented by y = -4/9x + 5, the slope of the new line is also -4/9. The line crosses the x-axis at x = 36, which means the y-intercept is 0.

Therefore, the equation in slope-intercept form of the line that crosses the x-axis at 36 and is parallel to the line represented by y = -4/9x + 5 is y = -4/9x + 0.

User Dane Brouwer
by
7.1k points
0 votes

Final answer:

The equation in slope-intercept form of the line that crosses the x-axis at 36 and is parallel to the line represented by y = -4/9x + 5 is y = -4/9x + 0.

Step-by-step explanation:

The equation in slope-intercept form of a straight line is given by y = mx + b, where m is the slope and b is the y-intercept.

Since the line is parallel to the line represented by y = -4/9x + 5, the slope of the new line is also -4/9. The line crosses the x-axis at x = 36, which means the y-intercept is 0.

Therefore, the equation in slope-intercept form of the line that crosses the x-axis at 36 and is parallel to the line represented by y = -4/9x + 5 is y = -4/9x + 0.

User Leonid Dashko
by
6.9k points
1 vote

Final answer:

The equation in slope-intercept form of the line that crosses the x-axis at 36 and is parallel to the line represented by y = -4/9x + 5 is y = -4/9x + 0.

Step-by-step explanation:

The equation in slope-intercept form of a straight line is given by y = mx + b, where m is the slope and b is the y-intercept.

Since the line is parallel to the line represented by y = -4/9x + 5, the slope of the new line is also -4/9. The line crosses the x-axis at x = 36, which means the y-intercept is 0.

Therefore, the equation in slope-intercept form of the line that crosses the x-axis at 36 and is parallel to the line represented by y = -4/9x + 5 is y = -4/9x + 0.

User Rupam
by
7.2k points