Question

(x^4-x^2-6)/(x^2+8) in quotient+ remainder
——————divisor.

Answer 1

To divide (x^4-x^2-6) by (x^2+8), we use long division and find the quotient and remainder.

Step-by-step explanation:

To divide (x^4-x^2-6) by (x^2+8), we use long division:

x^2x^2+8x^4-x^2-6x^4+8x^2-9x^2-6+48

The quotient is x^2+8 and the remainder is -9x^2-6+48 / (x^2+8).