Question

A pool ball leaves a 0.65-meter high table with an initial horizontal velocity of 2.5 m/s. Predict the time required for the pool ball to fall to the ground and the horizontal distance between the table's edge and the ball's landing location.

Answer 1

Using the principles of Physics, the pool ball will take approximately 0.364 seconds to hit the ground, and it will land about 0.91 meters away from the table's edge.

Step-by-step explanation:

The subject of the question is Physics, specifically dealing with the concepts of projectile motion and kinematics. To predict the time required for a pool ball to fall to the ground, we can use the formula for objects in free fall: t = √(2h/g), where h is the height and g is the acceleration due to gravity. For the horizontal distance, we can calculate using the equation d = vt, where v is the horizontal velocity and t is the time taken to fall.

Let's calculate the time first:

t = √(2h/g) = √(2 * 0.65 m / 9.8 m/s²) ≈ 0.364 s

The horizontal distance the ball travels before hitting the ground:

d = vt = 2.5 m/s * 0.364 s ≈ 0.91 m