Question

A yoyo of mass 0.65 kg makes a complete vertical circle in mid-air with a speed of 2.25 m/s. The vertical circle has a radius of 1.10 m. Determine the force of tension in the string at the side of the loop (perpendicular to the top/bottom).

Answer 1

The force of tension in the string at the side of the loop is 5.69 N.

Step-by-step explanation:

To determine the force of tension in the string at the side of the loop, we can use the concept of centripetal force. In this case, the tension in the string provides the centripetal force that keeps the yo-yo moving in a circular path. At the top of the loop, the force of tension must be greater than the weight of the yo-yo to keep it moving in a circle. According to the equation T - mg = mv^2/r, where T is the tension, m is the mass, g is the acceleration due to gravity, v is the speed, and r is the radius, we can calculate the force of tension. Plugging in the given values, we have T - (0.65 kg)(9.8 m/s^2) = (0.65 kg)(2.25 m/s)^2 / (1.1 m), which gives us T = 5.69 N.