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Given the following function find f(-1), f(0) and f(5) f(x)=2x+1f(x-1)=?

User Ronald Martin
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1 Answer

22 votes
22 votes

Solution:

Given the function:


f(x)=2x+1

To find f(-1), f(0), and f(5), we substitute the values of -1, 0, 5 respectively into the f(x) function.

Thus, we have

f(-1):


\begin{gathered} f(-1)=2(-1)+1=-2+1 \\ \Rightarrow f(-1)=-1 \end{gathered}

f(0):


\begin{gathered} f(0)=2(0)+1=0+1 \\ \Rightarrow f(0)=1 \end{gathered}

f(5):


\begin{gathered} f(5)=2(5)+1=10+1 \\ \Rightarrow f(5)=11 \end{gathered}

To find f(x-1), we substitute (x-1) for x into the f(x) function.

Thus,


\begin{gathered} f(x-1)=2(x-1)+1 \\ open\text{ parentheses,} \\ 2x-2+1 \\ simplify, \\ \Rightarrow f(x-1)=2x-1 \end{gathered}

User Mjuice
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