Final answer:
Displacement is the vector difference between the final and initial position, while the distance is the total path length traveled. Without specific position data for the iguana at 3 and 6 seconds, exact numerical answers cannot be provided.
Step-by-step explanation:
The student's question pertains to the concepts of displacement and distance in Physics, specifically regarding an iguana's horizontal position over time. To find the displacement, we need to know the initial and final positions of the iguana at times 3 and 6 seconds. Displacement is the shortest path between these two points and is a vector quantity. Distance, on the other hand, is the total length of the path taken by the iguana and is a scalar quantity.
To calculate the displacement, we would subtract the iguana's position at 3 seconds from its position at 6 seconds. Unfortunately, without the actual data of the iguana’s position at these times, we can't provide numerical answers. However, if we were given a position versus time graph or a set of positions at the designated times, we could use the information to find the displacement and distance.
For distance, we would add up the absolute values of the changes in position during the time intervals to account for the to and fro movement.