Final answer:
The value of f(x) when x = 4 in the function f(x) = 2x^2 + 6 is 38.
Step-by-step explanation:
Given the function f(x) = 2x^2 + 6, we need to find the value of f(x) when x = 4.
Substituting x = 4 into the function, we get:
f(4) = 2(4)^2 + 6
f(4) = 2(16) + 6
f(4) = 32 + 6
f(4) = 38
Therefore, the value of f(x) when x = 4 is 38.