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What is the value of f(x) when x = 4 in the function f(x) = 2x^2 + 6?

a) 38
b) 22
c) 70
d) 54

1 Answer

4 votes

Final answer:

The value of f(x) when x = 4 in the function f(x) = 2x^2 + 6 is 38.

Step-by-step explanation:

Given the function f(x) = 2x^2 + 6, we need to find the value of f(x) when x = 4.

Substituting x = 4 into the function, we get:

f(4) = 2(4)^2 + 6

f(4) = 2(16) + 6

f(4) = 32 + 6

f(4) = 38

Therefore, the value of f(x) when x = 4 is 38.

User Almir Vuk
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