Final answer:
The acceleration of a 12,000 N car sliding down a frictionless 32-degree slope is 5.2 m/s², represented by option B.
Step-by-step explanation:
The acceleration of the car on a frictionless slope can be calculated using Newton's second law and the component of gravitational force acting along the slope. The force of gravity causing the car to accelerate down the slope is given by mg sin(θ), where m is the mass of the car, g is the acceleration due to gravity (9.8 m/s²), and θ is the angle of the slope (32 degrees in the problem). Since the slope is frictionless, the acceleration a of the car is just the gravitational component along the slope divided by the mass of the car:
a = g sin(θ)
Plugging the values into the equation, we have:
a = 9.8 sin(32°)
= 9.8 * 0.52992
≈ 5.2 m/s²
Therefore, the correct answer to the question is B. 5.2 m/s².